Sunday, February 18, 2007

NPR Puzzle

The Weekend Edition Sunday puzzle for this week is

Challenge for February 18: The object of this challenge is to develop nine different mathematical expressions that equal eight. You must use the digits 2, 7 and one other. And that other digit must be a one in the first expression, two in the next expression and so on, up to nine. You can use a digit once and only once in each expression.

You may use the four arithmetic symbols: plus, minus, times and divided by, as well as exponents and decimal points. You may use parenthesis as you need them. For example: Using the digits 2, 7 and 1 you can make the expressions 2+7-1= 8.

This week's Challenge is from Robert Waynewright in New Rochelle, N.Y.

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I'm currently stuck on 2,5,7, and 2,7,7.

15 comments:

  1. Anonymous4:52 PM

    Me too. When I went looking for blog comments, I kind of figured that this is what I'd find. The others are relatively easy; there is some complexity in these last too.

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  2. Anonymous6:14 PM

    Think about dividing decimals.

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  3. Anonymous11:44 PM

    7/.7 - 2

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  4. Anonymous11:48 PM

    .2*5 + 7

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  5. Ha, talk of being stuck in a groove.
    Anyway, the full set of answers is somewhere else on the site.

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  6. Anonymous12:46 PM

    somewhere else on this site??? im gettin killed on a couple of these!

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  7. Anonymous1:20 PM

    I'm stuck on 2,7,8. Any hints?

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  8. 2,7,8 - use decimals

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  9. Anonymous2:02 PM

    I have solutions for 0,2,7 (7+2**0) and 2,7,10 (2**(10-7)) but can't get 2,7,8. Any ideas?

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  10. Anonymous2:16 PM

    I'm pretty sure the question asks for numbers from 1-9, 0 not included. DOES ANYBODY KNOW 2,7,8???

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  11. Anonymous2:40 PM

    2,7,8 is a lot simpler than most of you imagine. It's simply 7.2 + .8, or 7.8 + .2.

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  12. Anonymous3:19 PM

    I'm stuck on 4 and 7!!!

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  13. Anonymous3:23 PM

    6...?

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  14. OK, I had them under "Excitement of Discovery", but here they are, including 0 (0 is not part of the NPR set).

    2^0 + 7
    2 + 7 - 1
    2/2 + 7
    (7 - 3) * 2
    2^(7-4)
    .5 * 2 + 7
    2*7 - 6
    7/.7 - 2
    7.2 + .8
    72/9

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  15. Anonymous2:15 PM

    Thanks. I have [(7+9)/2] for number 9 - I'm not sure how the 'digit' rule is to be interpretted. For 8 I have [7+(.2+.8)].

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